the sum of 1st 15 terms of 1+3+5....is
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1+3+5+......+15.
Here a=1, d=3-1=2, n=15.
We know that
Sn=n/2[2a+(n-1)d].
Sn=15/2[2(1)+(15-1)(2)].
Sn=15/2[2-(14)(2)].
Sn=15/2[2-28].
Sn=15/2[26].
Sn=15×13.
Sn=195.
Answer:- 195.
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