The sum of 1st and 9th term of an AP is 44. its 4th term is 18. What is its 6th term?
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Answer:
Here,
a4=a+3d
a8=a+7d
Therefore,
a+3d+a+7d=24
2a+10d=24
a+5d=12 …… (1)
Again,
a6=a+5d
a10=a+9d
Therefore,
a+5d+a+9d=44
2a+14d=44
a+7d=22 ……. (2)
Solving equations (1) and (2), we get
d=5 and a=−13
Therefore,
a1=a=−13
a2=a+d=−13+5=−8
a3=a+2d=−13+10=−3
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