the sum of 1st five term of Ap is 40 and the sum of next five term is 90 find the value of 1st term
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Answer:
first term=4
Step-by-step explanation:
S₅=40
S₁₀-S₅=90
S₅=5/2[2a+(5-1)d]
2a+4d=40*2/5
2a+4d=16.................(1)
S₁₀-S₅=90
S₁₀=90+S₅
S₁₀=90+40
S₁₀=130
S₁₀=10/2[2a+(10-1)d]
2a+9d=130/5
2a+9d=26...........(2)
eq2-eq1=>
2a+9d=26
- 2a+4d=16
0+ 5d =10
d=2
substitute d=2 in eq1
2a+4(2)=16
2a=16-8
a=8/2
a=4
first term=4
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