The sum of 1st n terms of an AP is given by sn=2n^2+3n find the sixteenth term
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Sn=2n^2+3n
let n=1
S1=2(1)^2+3(1)
S1= 2+3=5=a1
let n=2
S2= 2(2)^2+3(2)
S2= 2(4)+6
S2= 8+6=14
a1+a2=S2
5+a2=14
a2=9
a2-a1=d
9-5=4=d
a1=5,d=4
a16=a+(16-1)d
a16= a+15d
a16= 5+15(4)
a16= 5+60=65
hope it helps.
please mark it as brainliest.
let n=1
S1=2(1)^2+3(1)
S1= 2+3=5=a1
let n=2
S2= 2(2)^2+3(2)
S2= 2(4)+6
S2= 8+6=14
a1+a2=S2
5+a2=14
a2=9
a2-a1=d
9-5=4=d
a1=5,d=4
a16=a+(16-1)d
a16= a+15d
a16= 5+15(4)
a16= 5+60=65
hope it helps.
please mark it as brainliest.
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