The sum of 1st n termsof an AP is 3nsquare+6n find it nth term
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HI MATE...
Step-by-step explanation:
i am going to solve this question in a different way
given
sum=3n2+6n --(1)
replace n with n-1
sum=3(n - 1)^2 + 6(n-1)
=3(n^2 +1 -2n) + 6n-6
= 3n^2 + 3 -6n + 6n -6
= 3n^2 - 3 --(2)
now ,
subtracting 1 and 2 we get,
nth term =3n2+6n - (3n^2 -3)
= 6n + 3
now, let me explain, if the sum of first 5 is terms is 10 .This subtracted by sum of first 4 terms that is 8 then we will get the 5th term as 2.
I hope you get it now,
Please mark my answer as brainliest
faraanahmedhashmi:
please mark my answer as brainliest..
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