Question

the sum of 1st six consecutive terms of an arithmetic sequence is 111.
find the sixth term ? ​

Answer 1

x+(x+1)+(x+2)+(x+3)+(x+4)+(x+5)=111

6x+15=111

6x=111-15

6x=96

x=96÷6

x=16

first term =16,last term=21