Question

the sum of 2/3 and 4/5 of a number is 79/7 find the number​

Answer 1

Answer:

1185/133

Step-by-step explanation:

Let the number be 'x'

According to the question,

$\implies \dfrac{2}{3} x + \dfrac{4}{5} x = \dfrac{79}{7}\\\\\implies \dfrac{2x}{3} + \dfrac{3x}{5} = \dfrac{79}{7}\\\\\text{Taking LCM we get,}\\\\\implies\dfrac{2x\times 5 + 3x \times 3}{3 \times 5} = \dfrac{79}{7}\\\\\implies \dfrac{10x + 9x}{15} =\dfrac{79}{7}\\\\\text{Cross Multiplying we get,}\\\\\implies 19x \times 7 = 79 \times 15\\\\\implies 133x = 1185\\\\\implies x = \dfrac{1185}{133}$

Therefore the number is 1185/133.

Answer 2

Solutions:

Let the num be X.

2x/3 + 4x/5 = 79/7

(2x × 5) + (3x × 3) / (3 × 5) = 79/7

(10x + 9x) / 15 = 79/7

19x × 7 = 79 × 15

133x = 1185

x = 1185/133

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