Question

the sum of 2/3 and the additive inverse of 7/2 is​

Answer 1

Answer:

$\frac{-17}{6}$

Step-by-step explanation:

additive inverse of $\frac{7}{2}$ is -$\frac{7}{2}$

=> $\frac{2}{3}$ + (-$\frac{7}{2}$) = $\frac{2}{3}$ - $\frac{7}{2}$

               = $\frac{(2*2)-(7*3)}{2*3}$

               = $\frac{4-21}{6}$

               = $\frac{-17}{6}$