Question

The sum of 2 consecutive multiples of 3 is 429. Find the number

Answer 1

Answer:

The two consecutive multiples of 3  are 213 and 216.

Step-by-step explanation:

Let us consider the two consecutive multiple of 3 is $3x$ and $3(x+1).$

Given that,

               The sum of 2 consecutive multiples of 3 is 429.

                     $3x+3(x+1)=429\\ \\ 3x+3x+3=429\\ \\ 3x+3x=429-3\\ \\ 3x+3x=426\\ \\ 6x=426\\ \\ x=\frac{426}{6}=71$

The number are

                 $3x=3\cdot 71=213\\ \\ 3(x+1)=3(71+1)=3 \cdot 72=216$