Question

The sum of 2 consecutive multiples of 3 is 429 find the number

Answer 1

Answer:

The two consecutive multiples of 3 which give a sum of 429 will be 213 and 216

Step-by-step explanation:

Here it is given that the sum of 2 consecutive multiples of 3 is 429

We have to find both the numbers

So, if one multiple will be x, then the other multiple will be x + 3

So, x + x + 3 = 429

           2x + 3 = 429

                   2x = 429 - 3

                   2x = 426

                     x = 213

So, x + 3 = 213 + 3

              = 216

Answer 2

Answer:

So, the required numbers are $213$ and $216$.

Step-by-step explanation:

• In context to question asked,
• Sum of $2$ consecutive multiples of $3$ is $429$.
• We have to find that number.
• According to condition given, let, two consecutive multiples of $3$ be $3x$ and $3(x+1)$.
• So, the required equation becomes,

   $3x+3(x+1)=429$

  ∴ $3x+3x+3=429$

              ∴ $6x=429-3$

              ∴ $6x=426$

               ∴ $x=\frac{426}{6}$

                ∴ $x=71$

• Now, first multiple = $3x=3*71$ = $213$

      Second multiple = $3(x+1)=3(71+1)=3*72=216$

• So, the required numbers are $213$ and $216$.