Question

the sum of 2 conservative multiple of 10 is 210 find the smallest number

Answer 1

Answer:

let the two consecutive multiples of 10 be x and x+10

the sum of two consecutive multiples of 10 is 210

x+x+10 = 210

2x+10 = 210

2x = 210-10

2x = 200

x = 200/2

x = 100

smallest multiple = x = 100

largest multiple = x+10 = 100+10 = 110

Step-by-step explanation:

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Answer 2

The answer is 2

Step-by-step explanation:

The answer is 2