Question

The sum of 2 digit number& the number obtained by reversing the order of its digits is 121, and the a digits differ
by 3. Find the number.​

Answer 1

Answer:

33

Step-by-step explanation:

brainliest please

Answer 2

ANSWER:

• Original number can be 74 and 47.

GIVEN:

• Sum of two digit number and the number obtain by reversing the digit is 121.
• The digits differ by 3.

TO FIND:

• Original number

SOLUTION:

Let the digit at tens place is 'x'

Let the digit at once place be'y'

Original number = 10x+y

Reversed number = 10y+x

Case 1

=> 10x+y+10y+x = 121

=> 11x+11y = 121

=> 11(x+y) = 121

=> x+y = 121/11

=> x+y = 11. .....(i)

Case 2

When digit at tens place is greater than once place.

=> x-y= 3. ......(ii)

Adding eq (I) and (ii) we get ;

=> x+y+x-y = 11+3

=> 2x = 14

=> x = 7

Putting x=7 in eq(I)

=> 7+y = 11

=> y = 11-7

=> y = 4

Original number = 10x+y

= 10(7)+4

= 70+4

= 74

Case 3

When digit at once place is greater than tens place.

=> y-x = 3 .....(iii)

Adding eq (i) and (ii) we get ;

=> x+y+y-x = 11+3

=> 2y = 14

=> y = 7

Putting y = 7 in eq(I) we get;

=> x+7 = 11

=> x = 11-7

=> x = 4

Original number = 10x+y

= 10(4)+7

= 40+7

= 47