the sum of 2 digit number and number obtained by reversing the order of its digit is 165. if differ by 3 find the nummber
Answers
EXPLANATION.
- GIVEN
Sum of 2 digit number and the number
obtaining by reversing the order of its
digit = 165.
it is differ by = 3
To find the number.
According to the question,
Let the tens place be = x
Let the unit place be = y
original number = 10x + y
reversing number = 10y + x
Case = 1
Sum of 2 digit number and the number
obtaining by reversing the order of its
digit = 165.
=> 10x + y + ( 10y + x) = 165
=> 11x + 11y = 165
=> x + y = 15 ........ (1)
Case = 2
it is differ by = 3
=> x - y = 3 ..... (2)
From equation (1) and (2) we get,
=> 2x = 18
=> x = 9
put the value of x = 9 in equation (1)
we get,
=> 9 + y = 15
=> y = 6
Therefore,
Number = 10x + y = 10(9) + 6 = 96
original number = 96
Step-by-step explanation:
- The sum of a two digit number and number obtained by reversing the digits is 165.
- The difference of the digits = 3
- The number.
Let the ones digit of the number be y
The tens digit of the number = x
The original number = 10x + y
The reversed number = 10y + x
According to the 1st condition
Dividing the whole equation by 11
According to the 2nd condition :-
The digits differ by 3
Adding equation (i) and (ii)
______________
Substituting x = 9 in equation (ii)
Now:-
Substitute x = 9 and y = 6 in 10x + y
= 10(x) + y
= 10(9) + 6
= 96