Math, asked by pranavkashyap2422, 9 months ago

the sum of 2 digit number and number obtained by reversing the order of its digit is 165. if differ by 3 find the nummber

Answers

Answered by amansharma264
89

EXPLANATION.

  • GIVEN

Sum of 2 digit number and the number

obtaining by reversing the order of its

digit = 165.

it is differ by = 3

To find the number.

According to the question,

Let the tens place be = x

Let the unit place be = y

original number = 10x + y

reversing number = 10y + x

Case = 1

Sum of 2 digit number and the number

obtaining by reversing the order of its

digit = 165.

=> 10x + y + ( 10y + x) = 165

=> 11x + 11y = 165

=> x + y = 15 ........ (1)

Case = 2

it is differ by = 3

=> x - y = 3 ..... (2)

From equation (1) and (2) we get,

=> 2x = 18

=> x = 9

put the value of x = 9 in equation (1)

we get,

=> 9 + y = 15

=> y = 6

Therefore,

Number = 10x + y = 10(9) + 6 = 96

original number = 96

Answered by MaIeficent
133

Step-by-step explanation:

\bf{\underline{\underline\red{Given:-}}}

  • The sum of a two digit number and number obtained by reversing the digits is 165.

  • The difference of the digits = 3

\bf{\underline{\underline\blue{To\:Find:-}}}

  • The number.

\bf{\underline{\underline\green{Solution:-}}}

Let the ones digit of the number be y

The tens digit of the number = x

The original number = 10x + y

The reversed number = 10y + x

According to the 1st condition

\longrightarrow \rm(10x + y) + (10y + x) = 165

\longrightarrow \rm10x + y+ 10y + x = 165

\longrightarrow \rm11x + 11y= 165

Dividing the whole equation by 11

\longrightarrow \rm \dfrac{11x}{11} + \dfrac{ 11y}{11}=  \dfrac{165}{11}

\longrightarrow \rm x + y=  15.....(i)

According to the 2nd condition :-

The digits differ by 3

\longrightarrow \rm x  - y=  3.....(ii)

Adding equation (i) and (ii)

 \rm x  \: +  \not y = 15

\rm x  \:  -   \not y = 3

______________

\rm  \longrightarrow 2x   = 18

\rm  \longrightarrow x   =  \dfrac{18}{2}

 \rm  \longrightarrow x   =  9

Substituting x = 9 in equation (ii)

 \rm\longrightarrow x - y = 3

\rm\longrightarrow 9 - y = 3

\rm\longrightarrow y =9- 3

\rm\longrightarrow y =6

Now:-

Substitute x = 9 and y = 6 in 10x + y

= 10(x) + y

= 10(9) + 6

= 96

\underline{\boxed{\rm\purple{\therefore The \: number =96}}}

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