the sum of 2-digit number is 11.the number obtained by interchanging the digit exceeds the original number by 27.find the number
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Given, the sum of digits of a two digit number is 7.
Let the digit at the one's place be x.
∴The digit at the ten's place is 7 – x.
Original number = 10 (7 – x) + x = 70 – 9x
Reverse number = 10x + 7 – x = 7 + 9x
7+9x=70-9x+27
9x+9x=70+27-7
18x=90
x=90/18
x=5
Again...
∴ Original number = 70 – 9x = 70 – 9 × 5 = 70 – 45 = 25
Let the digit at the one's place be x.
∴The digit at the ten's place is 7 – x.
Original number = 10 (7 – x) + x = 70 – 9x
Reverse number = 10x + 7 – x = 7 + 9x
7+9x=70-9x+27
9x+9x=70+27-7
18x=90
x=90/18
x=5
Again...
∴ Original number = 70 – 9x = 70 – 9 × 5 = 70 – 45 = 25
AFROZ123:
given is not 7 brother
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