Question

The sum of 2 digit number is 12.If the digits are reversed,the new number is 12 less than twice the original number.Find the number

Answer 1

x is the number in tenth place and y os the number in ones place

Answer 2

Answer:

The number is 48

Step-by-step explanation:

Given that the sum of 2 digit number is 12. If the digits are reversed, the new number is 12 less than twice the original number.

we have to find the two digit number.

Let the two-digit number is xy therefore the number becomes 10x+y

As the sum of 2 digit number is 12 that means

x+y=12     →   (1)

Now, if the digits are reversed, the new number is 12 less than twice the original number.

$10y+x=2(10x+y)-12$

$10y+x=20x+2y-12$

$19x-8y=12$       →     (2)

Solving (1) and (2), we get

(2)+8(1)  ⇒

$19x-8y+8x+8y=12+96$

$27x=108$

$x=\frac{108}{27}=4$

x+y=12 ⇒ 4+y=12 ⇒  y=8

Hence, the number is xy=48