Question

The sum of 2 digit number is 12 on reversing them the number increases by 18 find the original number

Answer 1

Step-by-step explanation:

The solution can be obtained by letting x be the 'tens digit', and y be the unit digit, so that the original number is 10x+y. Then 10x+y+18=10y+x, because the digits are reversed. This simplifies to 9x+18=9y, or x+2=y. Since the digits add up to 12, x+y=12.

Answer 2

$\huge\bold\purple{Answer:-}$

The sum of the digit of the two digit number is 12. When the digit are interchange, the result number is 36 more than the original number. What is the original number?

Let the unit digit=X

Tens digit=12-X

The number=10(12-X)+X

The number after reversal=10(X)+12-X

The equation

10(12-X)+X-36 =10X+12-X

120–10X+X-36=10X+12-X

-10X+X-10X+X=12–120–36

-18X=-144

18X=144

X=144/18

X=8x

X=unit digit=8

Tens digit=12–8=4

The number=10(4)+8=48

Reverse number=84

84 is 36 more than 48

So the desired number is 48