the sum of 2 digit number is 12 the number is 6 time s the unit digit find the number .
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Answer:
The sum of the digits of a 2-digit number is 12. The number is 48
Solution:
Let assume number at tens place = X
And number at units place = y
So number = 10x + y
Given that sum of two digits is 12
=> x + y = 12
=> y = 12 - x
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(1)
Also given number is 6 times the unit digit
=> 10x + y = 6y
=> 10x - 5y = 0
=> 2x - y = 0
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(2)
Substituting value of x from equation (1) in equation (2) we get
=>2x -( 12 x) = 0
=> 3x = 12
=>X = 4
From (2) y = 12 - x = 12 - 4 = 8
Hence required number is 10 x 4 + 8 = 48.
Step-by-step explanation:
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