the sum of 2 digit numbrr and number obtained by reversing the order of digits is 99.if the digits of number differ by 3.find the number.
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a/q : 10x+y + 10y+x = 99
11x+11y = 99
x+y= 9.......1
x-y = 3.....2
x= 3+y
Substituting this in eq 1
3+y+y = 9
2y=6
y=3
So in eq2
x-y=3
x-3=3
x=6
so y= 3 and x=6
no. is 36 or 63 is your answer
HOPE IT HELPS YOU FRIEND.......
11x+11y = 99
x+y= 9.......1
x-y = 3.....2
x= 3+y
Substituting this in eq 1
3+y+y = 9
2y=6
y=3
So in eq2
x-y=3
x-3=3
x=6
so y= 3 and x=6
no. is 36 or 63 is your answer
HOPE IT HELPS YOU FRIEND.......
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