The sum of 2 digits number and number obtain by interchanging digits is 132. If the two digit differ by 2 find the number
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Answered by
3
Let us assume the x and y are the two digits of a two-digit number
Therefore, two-digit number = 10x + y and number obtained by interchanging the digit is = 10y + x
Given:
10x + y + 10y + x = 132
11x + 11y = 132
x + y = 12
x = 12 – y ------------1
Also given that:
x – y = 2 ----------2
Substitute the value of x from eqn 1 in the eqn 2
12 – y – y = 2
2y = 10
y = 5
Therefore, x = 12 – 5 = 7
Two digit number is = 10x + y = (10 * 7) + 5 = 75
and the number obtained by interchanging the digits is = 10y + x = 10*5 + 7 = 57.
Read more on Brainly.in - https://brainly.in/question/567483#readmore
Therefore, two-digit number = 10x + y and number obtained by interchanging the digit is = 10y + x
Given:
10x + y + 10y + x = 132
11x + 11y = 132
x + y = 12
x = 12 – y ------------1
Also given that:
x – y = 2 ----------2
Substitute the value of x from eqn 1 in the eqn 2
12 – y – y = 2
2y = 10
y = 5
Therefore, x = 12 – 5 = 7
Two digit number is = 10x + y = (10 * 7) + 5 = 75
and the number obtained by interchanging the digits is = 10y + x = 10*5 + 7 = 57.
Read more on Brainly.in - https://brainly.in/question/567483#readmore
Answered by
3
let us take the tens digit be 'x' and the unit digit be 'y'
and the original no. be 10x+y and the interchanged no. will be 10y+x
according to question,
10x+
and the original no. be 10x+y and the interchanged no. will be 10y+x
according to question,
10x+
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