Question

The sum of 2 natural numbers is 28 and their product is 192. Find the number.

Answer 1

Sum of two natural numbers=28
Product=192
So, let the numbers be x and y
x +y=28
x=28-y ------(1)
xy=192 -------(2)

(28-y)(y)=192
28y-y²=192
28y -y²-192= 0
y²-28y+192=0
y²-(16+12)y+192=0
y²-16y-12y+192=0
y(y-16)-12(y-16)=0
(y-16)(y-12)
y-16=0
y=16,12
Thus 16 is x and 12 is y or vice versa...

Hope it helps☺☺

Answer 2

Holla ^_^

☸ Required Answer is ⬇ ⬇⬇ ⬇

⭐ let the numbers be x nd y .

A.T.Q

➡ x+y = 28 ......... (i)

➡. xy = 192
x = 192/y

Put x = 192/y in eq. (i)

192/y + y =28

192+y² / y = 28

192+y² = 28y

y² - 28y + 192

y² - 16y - 12y +192

y (y-16) -12(y-16)

(y-16) (y-12)

➡ y = 16 or y = 12

Putting values of y in eq (i)

➡ x = 12 or x = 16 .


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