Question

The sum of 2 natural numbers is 28 and their product is 192. find the number.

Answer 1

$\color{blue}{Let the required numbers be x and (28 − x). According to the given condition, x(28−x)=192⇒28x−x2=192⇒x2−28x+192=0⇒x2−16x−12x+192=0 ⇒x(x−16)−12(x−16)=0⇒(x−12)(x−16)=0⇒x−12=0 or x−16=0⇒x=12 or x=16$
Hello here is your answer:-

Answer 2

let the numbers be x and y
x+y=28=>x=28-y
xy=192
(28-y)y=192
28y-y^2=192
y^2-28y+192=0
y^2-16y-12y+192=0
y(y-16)-12(y-16)=0
(y-16)(y-12)=0
y-16=0. y-12=0
y=16 y=12
if y=16 then x=28-16=12
if y=12 then x=28-12=16
so the two Natural numbers are 12 and 16