Question

the sum of 2 no is 64 and the second no is 16 less then the first find the no​

Answer 1

Answer:

x=40

y=24

Step-by-step explanation:

x+y=64

x+x-16=64(second no is 16 less then the first)

2x=80

x=40

40-16=y

y=24

Answer 2

Step-by-step explanation:

Let the No. be x

So second number = x -16

The equation so formed is,

x + x - 16 = 64

2x + 16 = 64

2x = 64 + 16

2x = 80

x = 80 ÷ 2

x= 40

So the first number is 40

Second number = 40 - 16

= 24

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