Question

the sum of 2 number is 80 and greater number is 11 more than twice the smaller no.Find the number​

Answer 1

Answer:

Small no is 23 and Greater no is 57

Step-by-step explanation:

Step 1: Assign the Greater number letter x and Smaller number letter y

So, sum of 2 numbers' equation will be x + y = 80 ---- Equation 1

Step 2: Create second equation based on the additional information

So, greater number is 11 more than twice the smaller no

x = 2y + 11 ---Equation 2

Step 3: replace x in Step 1 with the value in Equation 2

So, x + y = 80 becomes (2y + 11) + y = 80

3y + 11 = 80

3y = 69

Divide by 3 both sides, y = 69/ 3 = 23

Step 4: Apply y =23 in Equation 1

x + 23 = 80

x = 80 - 23

x = 57

Step 5: Testing the values

Sum of 2 numbers: 23 + 57 = 80

Greater number is 11 more than twice the smaller no

57 - 11 = 46

46 is twice 23