The sum of 2 number is 9 and sum of their receiprocal is 1\2.Find the number.
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⇒ Let one number be x, then other number will be 9−x
According to the question,
⇒
x
1
+
9−x
1
=
2
1
⇒
x(9−x)
9−x+x
=
2
1
⇒
9x−x
2
9
=
2
1
⇒ 2(9)=9x−x
2
⇒ 18−=9x−x
2
⇒ x
2
−9x+18=0
⇒ x
2
−6x−3x+18=0
⇒ x(x−6)−3(x−6)=0$
⇒ (x−6)(x−3)=0
⇒ x−6=0 and x−3=0
∴ x=6 and x=3
⇒ One number is 6 and other number is 3
⇒ The sum of squares of the numbers =(6)
2
+(3)
2
=36+9=45
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