Question

The sum of 2 numbers is 16 and the sum of their reciprocals is 1/3. Find the number

Answer 1

Answer:

Ans : 4,12

Step-by-step explanation:

Let the the parts be x and y

x+y=16

⇒x1+y1=31

⇒xy16=31

⇒y2−16y+48=0

⇒(y−12)(y−4)=0

⇒y=4 x=12,or y=12,x=4

Answer 2

Answer:

GIVEN:

sum of two numbers = 16

sum of their reciprocals = 1/3

RTP:

find the numbers

SOLUTION:

let one number be = x

other number be = 16 - x

=> 1/x + 1/16-x = 1/3

=> (16-x + x) / 16x - x^2 = 1/3

=> 16×3 = 16x - x^2

=> x^2 - 16x + 48 = 0

=> x^2 - 4x - 12x + 48 = 0

=> x( x - 4 ) - 12( x - 4 ) = 0

=> ( x - 12 ) ( x - 4 ) = 0

=> x = 12 , x = 4

therefore the two numbers are 12 and 4

i think this is the answer..........I hope this helps u