The sum of 2 numbers is 18650. If one of the addends is four times the other addend, what is the value of the smaller addend
Answers
Answered by
1
let the smaller addend be x
thus another addend be 4x
sum of them =5x = 18650
x=18650÷5
=3730
thus another addend be 4x
sum of them =5x = 18650
x=18650÷5
=3730
Answered by
4
Answer:
Value of smaller addend is 3730.
Step-by-step explanation:
Given :-
- The sum of two numbers is 18650.
- One of the addends is four times the other addend.
To find :-
- Value of smaller addend.
Solution :-
Consider,
- One addend = x
- Other addend = y
According to the 1st condition,
- The sum of two numbers is 18650.
x + y = 18650...............(i)
According to the 2nd condition,
- One of the addends is four times the other addend.
x = 4y................(ii)
Now take eq(i) and put x = 4y from eq (ii).
x + y = 18650
→ 4y + y = 18650
→ 5y = 18650
→ y = 18650/5
→ y = 3730
Now put y = 3730 in equation (ii)
x = 4y
→ x = 4×3730
→ x = 14920
Therefore, the value of smaller addend is 3730.
Similar questions