The sum of 2 numbers is 45 and their difference is 500 what is the answer??
Answers
Answered by
0
Let numbers be x and y.
x+y=45
=> x = 45-y
x*y = 500
=> y(45-y) = 500
=> 45y -y^2 = 500
=> y^2 -45y + 500 = 0
=> y^2 -25y -20y + 500 = 0
=> y(y-25) -20(y-25) = 0
=> (y-20)(y-25) = 0
so, y=20 , x =25
or y = 25 , x =20
numbers are 20 and 25.
Answered by
0
Step-by-step explanation:
let first number=x
let second number=y
x-y=500
x=500+y :-(1)
x+y=45
500+y+y=45 (putting value of x from 1)
y+y=45-500
2y=-455
y=-227.5
x=500+y
x=500-227.5
x=272.5
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