Question

The sum of 2 numbers is 45 and their product is 500

Answer 1

Answer:

$x + y = 45 - - - - (1) \\ xy = 500 - - - - - - (2) \\ from \: 2nd \: equation \\ x = \frac{500}{y} \\ put \: the \: value \: of \: x \: in \: equation \: 1 \\ \frac{500}{y } + y = 45 \\ y^{2} - 45y + 500 = 0 \\ y^{2} - 25y - 20y + 500 = 0 \\ y(y - 25) - 20( y - 25) = 0 \\ (y - 25)(y - 20) = 0 \\ y - 25 = 0 \: \: \: y - 20 = 0 \\ y = 25.y = 20$

Answer 2

Answer:

x+x=45

x*x=500

Step-by-step explanation:

A+B=45

A=45-B-----equation 1

A*B=500

By equation 1

substitute in A*B=500

(45-B)*B=500

-B^+45B=500

B^+45B-500

factorise

B^+25B+20B+500=0

B(B+25)+20(B+25)

B+25,B+20 are factors numbers are -25 ,-20