Question

The sum of 2 numbers is 45 and their ratio is 7:8 .find the numbers

Answer 1

number 1 = m
number 2 = n
m+n = 45
m/n = 7/8
We combine:
(m+n)/n = 15/8
45/n = 15/8
15n = 45*8
n = (45*8)/15
n = 24
m+n = 45
m = 45-24 = 21

Answer 2

Answer:

$let \: the \: two \: numbers \: be \: 7x \: and \: 8x$

$given \: their \: sums \: is \: 45$

$therefore \: 7x + 8x = 45$

$= > 15x = 45$

$= > x = \frac{45}{15}$

$= > x = 3$

$therefore \: two \: numbers \: are$

$7x = 7 \times 3 = 21$

$and$

$8x = 8 \times 3 = 24$