Question

The sum of 2 numbers is 80 and the greater number exceeds the smaller number by 11 . Find the numbers
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Answer 1

Answer:

let the no.be =x and (x+11)

=x+x+11=80

=2x+11=80

=2x=80-11

=2x=69

=x=69/2

=x=34.2

one number=34.2

other number=34.2+11

=45.2

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Answer 2

AnswEr :

Let us assume that the 1st no.[greater] be x & 2nd no.[smaller] be y.

Now,

According to the question, we'll form the equations and further we'll symplify them!

• Case - I

Sum of the 2 numbers is 80.

x + y = 80⠀⠀⠀⠀⠀⠀eqn(1).

• Case - II

The greater number exceeds the smaller number by 11.

x = y + 11⠀⠀⠀⠀⠀⠀eqn(2).

Now, substitute the value of x in eqn(1).

$:\implies \sf \: x + y = 80 \\ \\ \\:\implies \sf \: y + 11 + y = 80 \\ \\ \\ :\implies \sf \:2y = 80 - 11 \\ \\ \\ :\implies \sf \:2y = 69 \\ \\ \\:\implies \sf \:y = \dfrac{69}{2} \\ \\ \\:\implies \sf \:{ \boxed{ \frak{ \purple{y = 34.5}}}} \: \bigstar$

Substitute the value of y in eqn(2).

$:\implies \sf \: x = y + 11 \\ \\ \\:\implies \sf \: x = 34.5 + 11 \\ \\ \\:\implies \sf \: { \boxed{ \frak{ \red{x = 45.5}}}} \: \bigstar$

Therefore,

• Greater Number = x = 45.5

• Smaller Number = y = 34.5