The sum of 2 numbers is 95. if one exceeds other by 15 , then the smaller of the 2 is
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let num be x
another no be x+15
x+x+15=95
2x+15=95
2x=80
x=40
x+15=55
Smmaler no of two is 40=x
another no be x+15
x+x+15=95
2x+15=95
2x=80
x=40
x+15=55
Smmaler no of two is 40=x
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Answered by
1
let the first number be x
therefore the second number = x+15
as per question
x+x+15=95
2x+15=95
2x=95-15
2x=80
x=80/2
x=40
therefore the first number =x=40
second number=x+15=40+15=55
therefore the second number = x+15
as per question
x+x+15=95
2x+15=95
2x=95-15
2x=80
x=80/2
x=40
therefore the first number =x=40
second number=x+15=40+15=55
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