Question

The sum of 2 rational numbers is -3/8.If one of them is 3/16,find the other.

Answer 1

Given

$\bold{Sum \ of \ 2 \ rational \ numbers} = \dfrac{-3}{8}$

$\bold{One \ of \ the \ rational \ numbers} = \dfrac{3}{16}$

Let the other rational number be x.

$\implies x+ \dfrac{3}{16} = \dfrac{-3}{8}$

$\implies x = \dfrac{-3}{8}-\dfrac{3}{16}$

$\implies x = \dfrac{-6-3}{16}$

$\implies x = \dfrac{-9}{16}$

$\boxed{\boxed{\bold{Therefore, \ the \ other \ rational \ number \ is \ \frac{-9}{16}}}}}}}}}}$

                                                                               

Answer 2

Sum of two rational number  = $\huge\frac{-3}{8}$

One rational number = $\frac{3}{16}$

LET THE OTHER NUMBER BE $x$

=  $x+\frac{3}{16}=\frac{-3}{8}$

=  $x=\frac{-3}{ 8} - \frac{3}{16}$

=  $x = \frac{-6-3}{16}$

=  $x = \frac{-9}{16}$

The other rational number is  $\frac{-9}{16}$