The sum of - 2 x+ 3 y and 4 y + 3 x is
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(x+3y−4z)+(2x+y−z)+(−2x+3y−z)−(2x−4y+3z)
=(x+2x+3y+y−4z−z)+(−2x+3y−z)−(2z−4y+3z)
=(3x+4y−5z)+(−2x+3y−z)−(2x−4y+3z)
=(x+7y−6z)−(2x−4y+3z)
=x−2x+7y+4y−6z−3z
=−x+11y−9z
∴ Ans :−(−x+11y−9z)
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Answer:
=-2x+3y+4y+3x
=-2x+3x+3y+4y
=x+7y
Step-by-step explanation:
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