Question

the sum of 20 terms is440.if it's first term is 3.Find it's 20 th term
​

Answer 1

$</p><p>\huge\red{answer}$

$s _{20} = 440 \\ a = 3 \\ s _{20} = \frac{20}{2} (6 + (19)d) \\ \frac{44 - 6}{19} = d \\ = \frac{38}{19} = d \\ d = 2 \\ l = a + (n - 1)d \\ = 3 + (20 - 1)2 \\ = 3 + 38 \\ = 41$