The sum of 20 terms of log2+log4+log8+..... is
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Answered by
3
log 2 + log 4 + log 8 + … + log 1024 (10th term would be 2^10)
= log 2 + log (2^2) + log (2^3) + … + log (2^10)
= log 2 + 2 log 2 + 3 log 2 + …. + 10 log 2
= 55 log 2
Hope it helped :)
Rexplosion:
options are 20log2, log20, 210log2 and log2
Answered by
0
Answer:
210log 2
Step-by-step explanation:
log2+log(2^2)+log(2^3)+ ... log(2^20)
1log^2+2log^2+3log^2+...20log^2
(1+2+3+...20)log2
210log2
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