Question

the sum of 20 terms of progression 3+8+13+..... .​

Answer 1

Answer:

1010

Step-by-step explanation:

Here n=20, a=2, and d=5

Therefore, Sn= n/2(2a+(n-1)d)

S20= 10(6+95) {Substituting the values}

S20= 10 X 101

S20= 1010

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