Math, asked by anju5732, 6 months ago

The sum of 25 consecutive even integers is 10,000. What is the largest of these 25 consecutive integers?

Answers

Answered by mathnscience
4

Answer:

424

Step-by-step explanation:

n , n+2 , n+4 ,............. n+48

25n + ( 2+4+6+........48) =10000

25n + ( 24*25) = 10000

25n = 10000- 600 = 9400

n= 9400/ 25 = 3 7 6

largest number 376 + 48 = 4 24

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