Math, asked by SusanAabidi9496, 1 year ago

The sum of 2digit no is 8 .If their sum is 4times their differences find the numders by 10 class method

Answers

Answered by minnie147
0

Let the tens digit be x and the unit digit be y.

Therefore, the number is 10x+y.

According to the first condition, we get

x + y = 8 -----------(1)

According to the second condition, we get

(x+y) = 4 (x-y)

x + y = 4x - 4y

4x - 4y - x - y = 0

3x - 5y = 0 -----------(2)

Now, equation (1) becomes

x = 8 - y -----------(3)

Substitute the value of x from eqⁿ (3) in eqⁿ (2), we get

3(8 - y) - 5y = 0

24 - 3y - 5y = 0

24 - 8y = 0

8y = 24

y = 24/8

y = 3

Substitute the value y = 3 in eqⁿ (3), we get

x = 8 - 3

x = 5

Hence, x = 5 and y = 3.

Therefore, the number is 10×5 + 3= 50 + 3 = 53.

Answered by shivam7448
0

Let the tens digit be x and the unit digit be y.

Therefore, the number is 10x+y.

According to the first condition, we get

x + y = 8 -----------(1)

According to the second condition, we get

(x+y) = 4 (x-y)

x + y = 4x - 4y

4x - 4y - x - y = 0

3x - 5y = 0 -----------(2)

Now, equation (1) becomes

x = 8 - y -----------(3)

Substitute the value of x from eqⁿ (3) in eqⁿ (2), we get

3(8 - y) - 5y = 0

24 - 3y - 5y = 0

24 - 8y = 0

8y = 24

y = 24/8

y = 3

Substitute the value y = 3 in eqⁿ (3), we get

x = 8 - 3

x = 5

Hence, x = 5 and y = 3.

Therefore, the number is 10×5 + 3= 50 + 3 = 53.

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