The sum of 2digit no is 8 .If their sum is 4times their differences find the numders by 10 class method
Answers
Let the tens digit be x and the unit digit be y.
Therefore, the number is 10x+y.
According to the first condition, we get
x + y = 8 -----------(1)
According to the second condition, we get
(x+y) = 4 (x-y)
x + y = 4x - 4y
4x - 4y - x - y = 0
3x - 5y = 0 -----------(2)
Now, equation (1) becomes
x = 8 - y -----------(3)
Substitute the value of x from eqⁿ (3) in eqⁿ (2), we get
3(8 - y) - 5y = 0
24 - 3y - 5y = 0
24 - 8y = 0
8y = 24
y = 24/8
y = 3
Substitute the value y = 3 in eqⁿ (3), we get
x = 8 - 3
x = 5
Hence, x = 5 and y = 3.
Therefore, the number is 10×5 + 3= 50 + 3 = 53.
Let the tens digit be x and the unit digit be y.
Therefore, the number is 10x+y.
According to the first condition, we get
x + y = 8 -----------(1)
According to the second condition, we get
(x+y) = 4 (x-y)
x + y = 4x - 4y
4x - 4y - x - y = 0
3x - 5y = 0 -----------(2)
Now, equation (1) becomes
x = 8 - y -----------(3)
Substitute the value of x from eqⁿ (3) in eqⁿ (2), we get
3(8 - y) - 5y = 0
24 - 3y - 5y = 0
24 - 8y = 0
8y = 24
y = 24/8
y = 3
Substitute the value y = 3 in eqⁿ (3), we get
x = 8 - 3
x = 5
Hence, x = 5 and y = 3.
Therefore, the number is 10×5 + 3= 50 + 3 = 53.