the sum of 2digit number is 9 also 9 time this number is twice the number obtained by reversing te digits find the numer
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0
Answer:
18
Step-by-step explanation:
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2
Answer:
Let the ones place digit be y and tens place ne x ....
Therefore no.formed= 10x+y
No. formed on reversing the digit = 10y+x
ATQ:
x+y=9-------( Equation: 1)
9(10x+y)= 2 (10y+x)
90x + 9y = 20y + 2x
90x - 2x = 20y - 9y
88x = 11y
8x = y --------( Equation:2)
Placing (2) in (1)
x+y= 9
x+8x=9
9x=9
x= 1
y= 8x = 8×1= 8
Therefore no. = 10x+y
= 10×1 + 8 = 18
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