Question

The sum of 2nd term and 30th term of an arithmetic sequence is 50.Find the sum of 15th term and 17th term.

Answer 1

Answer:

2nd term = a + d

30th term = a + 29d

(a + d) + (a + 29d) = 50

2a + 30d = 50_______"' ( I )

Now, 15th term = a + 14d

17th term = a + 16d

So, (a + 14d) + (a + 16d)

= 2a + 30d

= 50 ( from ( I ) )

Hence, sum of 15th and 17th term is also equal to 50.....

Thanks!

Answer 2

Answer:

2nd term = a +d

30th term = a + 29d

(a + d) + (a + 29d) = 50

2a + 30d = 50_ __"" (1)

Now, 15th term = a + 14d

17th term = a + 16d

So, (a + 14d) + (a + 16d)

= 2a + 30d

= 50

(from (1))

so, sum of 15th and 17th term is equal to 50