Question

The sum of 3/4th of A’s salary and 5/3rd of B’s
salary is ₹16,000. The difference of their salaries is
₹2000. If B’s salary is less than that of A, then what
is the salary of B (in ₹)?

(a) 8000 (b) 2000

(c) 6000 (d) 12,000​

Answer 1

☯️ Answer :-

Therefore ,

• B ' s salary is Rs. 6000.

 Step-by-step-Explaination :-

Step 1 :

➢Assume salary of A and B

• Let A' s salary be Rs. X.
• Let B' s salary be Rs. Y.

❍ Given :-

• Sum of 3/4 th of A' s salary and 5/3 rd of B' s salary is Rs. Rs. 16000 .
• Also , Difference of their salaries is Rs. 2000 , where B' s salary is less than that of A' s salary.

❍ Find :-

• Salary of B in Rs.

❒ Solution :-

As , their fraction is given , So we have to add either x or y with them .

$\rm \dfrac{3}{4} x + \dfrac{5}{3} y = 16000$

Now , doing L.C.M of 4 and 3 (Denominator) .

$\dashrightarrow \rm \dfrac{(3 \times 3)x + (5 \times 4)y}{12} + = 16000$

$\dashrightarrow \rm \dfrac{9x + 20y}{12} + = 16000$

Now , what happens that this 12 as denominator will go to R.H.S and will be multiplied.

$\dashrightarrow \rm {9x + 20y} = 192000 \: { \huge \}} \bf \: equation \: 1\:\maltese$

$\dashrightarrow \rm {x - y} = 2000 \: { \huge\}} \bf \: equation \: 2\:\maltese$

$\dashrightarrow \rm x = 2000 + y{ \huge \}} \bf \: equation \: 3\:\maltese$

✡Putting value of x in equation 1 :-

$\rm \: 9x + 20y = 192000$

$\rm \: \dashrightarrow 9(2000 + y) + 20y = 192000$

$\rm \: \dashrightarrow 18000 + 9y + 20y = 192000$

$\rm \: \dashrightarrow 18000 + 29y = 192000$

Now , 18000 moves to R.H.S and becomes negative,

$\rm \: \dashrightarrow 29y = 174000$

$\rm \: \dashrightarrow y = \cancel\dfrac{174000}{29}$

$\rm \: \dashrightarrow \bf y = Rs. \: 6000 \:$

Hence, Value of Y is 6000 that is salary of B is Rs. 6000 .

$\sf {\therefore }\: \bf B' s \:salary \:is\:Rs. 6000$

✪ Question & Answer

The sum of 3/4th of A’s salary and 5/3rd of B’s salary is Rs.16,000. The difference of their salaries is Rs.2000. If B’s salary is less than that of A, then what is the salary of B (in Rs)?

• 8000
• 2000
• 6000 ✔
• 12,000

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Answer 2

QUESTION:-

The sum of 3/4th of A’s salary and 5/3rd of B’s

salary is ₹16,000. The difference of their salaries is

₹2000. If B’s salary is less than that of A, then what

is the salary of B (in ₹)?

SOLUTION:-

Let be A and B salary as x and y respectively

3/4x+5/3y=16000

9x+20y/12=16000

9x+20y=192000____1

x-y=2000____2

x=2000+y_____3

substitute in 1 equations

9(2000+y)+20y=192000

18000+9y+20y=192000

29y=192000-18000

y=174000/29

y=6000

B salary=₹6000