Question

The sum of 3 alternate multiples of 13 is 468. The value of the largest multiple is

Answer 1

Step 1:

Given Data: Sum of 3 consecutive multiples of 13 is 429  

Step 2:

Assume:

One number = x

Second Number = x + 13

Third Number = x + 26

x + (x + 13) + (x + 26) = 429  

x + x + 13 + x + 26 = 429  

3x + 39 = 429  

3x = 429 - 39  

3x = 390  

x = 390/3

x = 130  

Step 3:

First Number = 130

Step 4:

Value of (x + 13)  

130 + 13

= 143  

Second Number = 143

Step 5:

Value of (x + 26)  

130 + 26

= 156  

Third Number = 156  

Step 6:

Check if 130, 143 and 156 are Consecutive Multiples of 13 or not.  

130 ÷ 13

= 10

143 ÷ 13

= 11

156 ÷ 13

= 12  

Answer 2

Answer:

182

Step-by-step explanation: