the sum of 3 consecutive even integers is 66. find all the three integers.
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Answered by
6
Answer:
let first no. be x
second even np. be x+2
third no. be x+4
according to question
x+x+2+x+4=66
3x+6=66
3x=60
x=20
second no. 22
third no.24
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Answered by
2
Answer:
let the first no.be x
x+x+x=66
3x=66
x=66÷3
x=22
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