Question

The sum of 3 consecutive even integersis 66. find all the three integers​

Answer 1

Answer:

So the three numbers are: 20,22,24

Answer 2

Answer:

let the 1st integer be x

2nd integer be x+2

3rd integer be x+2+2

Sum of integers = x + x + 2 + x + 2+ 2

66 = 3x + 6

66-6 = 3x

60 = 3x

60/3 = x

20 = x

1st integer = x = 20

2nd integer = x+2 = 20+2 = 22

3rd integer = x+2+2 = 20+4 = 24