the sum of 3 consecutive even naturals numbers is 48 .find the greatest of the numbers.
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Answered by
4
let the three consecutive no. be s, x+1, x+2.
x+x+2+x+4=48
3x+6=48
3x=48-6
3x=42
x=42/3
x=14
now,
x=14 so,
x+1= 14+2= 16
x+2= 14+4= 18
the greatest even number= 18
hope it helps you
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x+x+2+x+4=48
3x+6=48
3x=48-6
3x=42
x=42/3
x=14
now,
x=14 so,
x+1= 14+2= 16
x+2= 14+4= 18
the greatest even number= 18
hope it helps you
Mark as brainliest
khushirai12:
plz mark as brainliest
Answered by
3
Let the the three consecutive even natural
numbers be x, x+2 and x+4
According to the question
x+x+2+x+4=48
3x+6 =48
3x =48-6
3x = 42
x = 42/3
x = 14
Greatest number= x+4 = 14 +4=18
numbers be x, x+2 and x+4
According to the question
x+x+2+x+4=48
3x+6 =48
3x =48-6
3x = 42
x = 42/3
x = 14
Greatest number= x+4 = 14 +4=18
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