Question

the sum of 3 consecutive integer is 27 then find all numbers

Answer 1

Let first integer =x
second integer=x+1
Third integer =x+2
a/q
x+x+1+x+2=27
3x+3=27
3x=27-3=24
3x=24
x=24/3=8
so, First integer=8
second integer=8+1=9
Third integer=8+2=10
so consecutive integer=8,9,10.answre.
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Answer 2

HeY MatE !!

HerE IS YouR AnsweR —————

let the first consecutive integer = $x$

so, the next two consecutive integers =$(x + 1), (x + 2)$

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acc. to the given condition ———

$= > x + (x + 1) + (x + 2) = 27 \\ \\ = > x + x + x + 3 = 27 \\ \\ = > 3x + = 27-3 \\ \\ = > 3x = 24 \\ \\ = > x = \frac{24}{3} \\ \\ = > x = 8$
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therefore ,

the first consecutive integer =

$x = 8$

the next two consecutive integers =

= (x + 1),(x + 2)

= (8 + 1),(8 + 2)

= 9, 10
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