Question

the sum of 3 consecutive integers is 309 the greatest of these integers is

Answer 1

hye

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the sum of 3 consecutive integers is 309 

lets first find the answer

=> let first number be x

then second will be x +1;third will be x +2

so lets form an equation

=> x+[x+1]+[x+2] = 309

=> 3x +3 = 309

=>3x = 309/3

=>3x = 103

=>x = 103/3

=>x = 34.3333...

= 34.34


=>so second number = 34.34 +1=  = 35.34

third number is x+2 = 36.34

so greatest is 36.34 

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hope it helps