Question

The sum of 3 consecutive integers is 45. what are these integers? ​

Answer 1

Answer:

let the integers be x, x+1, x+2

x+x+1+x+2 = 45

3x+3 = 45

3x = 45-3

3x = 42

x = 42/3

x = 14

so the integers are 14 ,

x+1 = 14+1 = 15,

x+2 = 14+2 = 16

the integers are 14,15,16.

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Answer 2

Answer:

Step-by-step explanation:

Call $n$ the first integer so you get:

$n + (n+1) + (n+2) = 45$

$3n + 3 = 45$

$3n = 42$

$n = 14$

The integers are: 14, 15, 16

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