Question

The sum of 3 consecutive integers is twice the smallest of the integer Find the number? ​

Answer 1

Solution

It is given that, sum of three consecutive Integers is twice the smallest integer.

Let the integers be x, x+1 and x+2.

According to Question,

→ x + x + 1 + x + 2 = 2x

→ 3x + 3 = 2x

→ 3x - 2x = -3

→ x = -3

Hence, three consecutive integers are -3, -2 and -1.

__________________________

VerificaTion:

→ -3 + (-2) + (-1) = 2(-3)

→ -3 - 2 - 1 = -6

→ -6 = -6

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Answer 2

Step-by-step explanation:

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ANSWER = 5,7,8