the sum of 3 consecutive maltipal of 3 is 333. find the multiple?
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Answered by
1
Hi ,
let x - 3 , x , x + 3 are three consecutive
multiples of the 3 .
according to the problem given,
their sum = 333
x - 3 + x + x + 3 = 333
3x = 333
x = 333/3
x = 111
Therefore ,
required 3 numbers are
x - 3 , x , x + 3
( 111 - 3 ) , 111 , ( 111 + 3 )
108 , 111 , 114
I hope this helps you.
Mark it as a brainliest
let x - 3 , x , x + 3 are three consecutive
multiples of the 3 .
according to the problem given,
their sum = 333
x - 3 + x + x + 3 = 333
3x = 333
x = 333/3
x = 111
Therefore ,
required 3 numbers are
x - 3 , x , x + 3
( 111 - 3 ) , 111 , ( 111 + 3 )
108 , 111 , 114
I hope this helps you.
Mark it as a brainliest
Answered by
6
Answer:
Hey mate here is your answer.....
---- three conecutive multiples are 108 , 111 and 114.
hope it's helpful for you..
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